Question

write chemical equation of the reaction of ethanoic acid with the following :
(1)sodium
(2)Sodium Hydroxide
(3)ethanol
write the name of one main product of each reaction.

Answer 1

a)CH3COOH+Na -------) CH3COONa+H2

CH3COONa----- sodium ethanoate

b)CH3COOH+NaOH --------) CH3COONa+H2O

CH3COONa ------- sodium ethanoate

c)CH3COOH+C2H5OH ---------) CH3COOC2H5+H2O

CH3COOC2H5 -------- Ethyl ethanoate(ester)

Answer 2

Explanation:

1) When ethanoic acid reacts with sodium metal it gives  hydrogen gas and salt of sodium ethanoate in aqueous as product .

$CH_3COOH(aq)+Na(s)\rightarrow CH_3COO^-Na^+(aq)+H_2(g)$

2)When ethanoic acid reacts with sodium hydroxide it gives water and salt of sodium ethanoate  in aqueous as product.

$CH_3COOH(aq)+NaOH(aq)\rightarrow CH_3COO^-Na^+(aq)+H_2O(l)$

3) When ethanoic acid reacts with ethanol it gives water and ester that is  Ethyl ethanoate  in aqueous as product.

$CH_3COOH(aq)+C_2H_5OH(aq)\rightarrow CH_3COOC_2H_5(aq)+H_2O(l)$