Write formula to determine magnetic moment and give identification of symbols in it.
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u=√n(n+2) n=no of unpaired electrons +nt
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IonConfigμso / B.M.μobs/ B.M.Ti(III)d1 (t2g1)√3 = 1.731.6-1.7V(III)d2 (t2g2)√8 = 2.832.7-2.9Cr(III)d3 (t2g3)√15 = 3.883.7-3.9Cr(II)d4 high spin (t2g3eg1)√24 = 4.904.7-4.9Cr(II)d4 low spin (t2g4)√8 = 2.833.2-3.3Mn(II)/ Fe(III)d5 high spin (t2g3eg2)√35 = 5.925.6-6.1Mn(II)/ Fe(III)d5 low spin (t2g5)√3 = 1.731.8-2.1Fe(II)d6 high spin (t2g4eg2)√24 = 4.905.1-5.7Co(III)d6 low spin (t2g6)00Co(II)d7 high spin (t2g5eg2)√15 = 3.884.3-5.2Co(II)d7 low spin (t2g6eg1)√3 = 1.731.8Ni(II)d8 (t2g6eg2)√8 = 2.832.9-3.3Cu(II)d9 (t2g6eg3)√3 = 1.731.7-2.2
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