Question

write kirchoof law and using it obtain the balance condition for weight stone brize
​

Answer 1

Answer:

We apply Kirchoff's current law in the shown circuit.

At junction B,

i

1

=i

g

+i

3

At junction D,

i

2

+i

g

=i

4

If current through the galvanometer is zero,

i

g

=0

thus i

1

=i

3

and i

2

=i

4

Applying Kirchoff's voltage law for loop ABDA,

i

1

P+i

g

G=i

2

R

Applying Kirchoff's voltage law for loop BCDB,

i

3

Q=i

4

S+i

g

G

When i

g

=0,

i

1

P=i

2

R

and i

3

Q=i

4

S

But i

1

=i

3

and i

2

=i

4

,

Therefore

Q

P

=

S

R

Answer 2

Answer:

We apply Kirchoff's current law in the shown circuit.

i1=ig+i3

​At junction D,

i 2+i g=i4f

current through the galvanometer is zero,

ig=0

thus, i1=i3

and i2 =i4

Applying Kirchoff's voltage law for loop ABDA,

i1P+ig

G=i2R

Applying Kirchoff's voltage law for loop BCDB,

i3 Q=i4S+i

gG When ig=0,i1

P=i2R and i3

Q=i4S But i1 =i 3 and i2=i 4,Therefore  Q/P= S/R

​ ​

Explanation:

hope this helps