Write the balanced equations for the reactions i) Hydrogen + Nitrogen→ Ammonia
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4
Hydrogen+oxygen----->Ammonia.
H2+N2------->NH3
3H2+N2------->2NH3
H2+N2------->NH3
3H2+N2------->2NH3
Answered by
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H2 + N2 ----› NH3
Now,
aH2 + bN2 ----› cNH3 .........(A)
here a,b and c are assumed stoichiometry coefficients.
For N --›
LHS = RHS
2b = c..........(1)
let's consider b = 1
then c = 2
For H --›
LHS = RHS
2a = 3c
2a = 3(2).......[since c = 2]
2a = 6
a = 6/2
a = 3
Put the values of a,b and c in the above equation (A)
3H2 + N2 ----› 2NH3
So, here you can see that,
H => 6 = LHS = RHS
N => 2 = LHS = RHS
Now,
aH2 + bN2 ----› cNH3 .........(A)
here a,b and c are assumed stoichiometry coefficients.
For N --›
LHS = RHS
2b = c..........(1)
let's consider b = 1
then c = 2
For H --›
LHS = RHS
2a = 3c
2a = 3(2).......[since c = 2]
2a = 6
a = 6/2
a = 3
Put the values of a,b and c in the above equation (A)
3H2 + N2 ----› 2NH3
So, here you can see that,
H => 6 = LHS = RHS
N => 2 = LHS = RHS
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