Question

write the coordinates of a point P on x axis which is equidistant from the point A (-2,0) and B (6,0)

Answer 1

Answer:

Step-by-step explanation:

(x, 0) is equidistant frm (-2,0) nd (6,0)

By distance formula

/(x-(-2))*2 + (0-0)*2 = /(x-6)*2 + (0-0)*2

On squaring both side

(x+2)*2= (x-6)*2

X*2+4-4x = x*2+36-12x

-4x+12x = 36-4

8x = 32

X=4

Hope it helps

Answer 2

The required point be "P(2, 0)".

Step-by-step explanation:

The given points be A (-2, 0) and B (6, 0).

Let the required point be P(x, 0).

To find, the value of x = ?

PA = PB

⇒ $PA^{2} =PB^{2}$

⇒$(x+2)^{2} +(0-0)^{2} =(6-x)^{2} +(0-0)^{2}$

⇒ $x^{2}+4x+4=x^{2}-12x+36$

⇒$4x+4=-12x+36$

⇒$4x+12x=36-4$

⇒ $16x=32$

⇒ x = 2

Hence, the required point be P(2, 0).