Question

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▶Question▶

→ the width of Ram's ground is 4 / 5 of its length. if its perimeter is 80 m, find its dimensions

Answer 1

$\huge\huge\bold{Answer}$

Let , length be = > x m
Breadth be = > $\frac{4}{5}$x m.

$\underline\textbf{Perimeter}$ = 2( length × breadth )

= 2 (x +$\dfrac{4}{5}$x)

= 2x + $\dfrac{8}{5}$x.

$\underline\textbf{According to question}$

= >2x + $\dfrac{8x}{5}$ = 80 m

= >10 x + 8x = 400.

= >18x = 400.
= >x = $\dfrac{400}{18}$ = 22.23

= >Now , time to find the breadth $\dfrac{4}{5}$ × 22.23 = 978 .12 m

Answer 2

Solution :

Let the length be 'Y' m.

Let breadth be 4/5y m.

We know that ,

Perimeter = ( L × B )

➨ 2 ( y + 4/5y )

➨ 2y + 8/5y

Now ,

➨ 2y + 8y/5 = 80

➨ 10y + 8y = 400

➨ 18y = 400

➨ y = 400/18 = 22.23 ( approx )

➨ y = 22.23

So ,

Breadth :-

➨ 4/5y = 4/5 × 22.23

➨ 17.78 m ( approx )