Question

Write the cubic polynomial whose roots are 3, 4, 1
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Answer 1

Answer:

$x^{3}-8x^{2}+19x-12=0$

Step-by-step explanation:

The cubic polynomial in 'x' with roots 3,4,1 is given by  $(x-3)(x-4)(x-1)=0$

=> $(x-3)(x^{2}-5x+4)=0$

=> $x^{3}-5x^{2}+4x-3x^{2}+15x -12=0$

=> $x^{3}-8x^{2}+19x-12=0$