Write the electronic configuration of 11n and 19k
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19
K,
3
Li,
11
Na,
4
Be
Electronic configurationof the following elements is:
19
K=2,8,8,1
3
Li=2,1
11
=2,8,1Na
4
Be=2,2
4
Be has smallest atomic radius because
19
K,
3
Li,
11
Na are present in same group 1 but Be is present in group 2. According to the trend, as we move from left to right atomic size of an atom decreases. Due to a large positive charge on the nucleus, the electrons are pulled closer to the nucleus, and the size of the atom decreases.
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