Write the expression for the rate law for the reaction 2NO+ 02=2NO2
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Answer:ANSWER
Here rate law is given as:-
rate=k[NO]
2
[O
2
]........(1)
[NO](concentration of NO) can be written as
V
n
where n=number of moles and V=volume
From (1)
rate=K[
V
n
]
2
[
V
n
]......(2)
Now,
Volume is related to 1/3
r
d
From V to
3
V
put new volume in (2)
New rate will be
r
′
=K[
V
3n
]
2
[
V
3n
]=K(3)
2
[
V
n
]
2
(2)[
V
n
]=27K[
V
3n
]
2
[
V
3n
]
so,
r
r
′
=
K[
V
n
]
2
[
V
n
]
27K[
V
3n
]
2
[
V
3n
]
=27
Rate of reaction changes by 27 times.
Explanation:
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