Write the first five terms of the following sequence whose nth term is a n equal to n square minus n + 1
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an=n (n+2)
let n=1 , a1=1 (1+2)=3
let n=2, a2=2 (2+2)=8
let n=3, a3=3 (3+2)=15
let n=4, a4=4 (4+2)=24
let n=5, a5=5 (5+2)=35
Ans:-First five terms of the sequence are:-3,8,15,24,35
if we subtract them I. e.
8-3=5,15-8=7,24-15=9,35-24=11
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