write the first three terms of the AP those common difference is -3 and the first term is 4
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a1=4
d=-3
so a2=a1+d=4-3=1
a3 = 1-3=-2
a4=-2-3=-5
d=-3
so a2=a1+d=4-3=1
a3 = 1-3=-2
a4=-2-3=-5
Answered by
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Answer:
So first three terms are 4 , 1 , -2
Step-by-step explanation:
In AP we can get terms by adding common difference of the terms
so
Now we have
a₁ = 4
d = -3
We know that
aₙ = a₁ + (n-1)d
Now
Second term is
a₂ = a₁ + (n-1)d
Here n = 2 so
a₂ = a₁ + (n-1)d
Putting values
a₂ = 4 + (2-1)(-3)
a₂ = 4 - 3
a₂ = 1
third term is
a₃ = a₁ + (n-1)d
Here n = 3 so
a₃ = a₁ + (n-1)d
Putting values
a₃ = 4 + (3-1)(-3)
a₃ = 4 -6
a₃ = -2
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