Question

write the oxidation state and covalency of al in alf6)3-

Answer 1

Answer: -

Oxidation state is + 3 and covalency is 6.

Explanation: -

The given radical is AlF₆³⁻

Now F fluorine has oxidation state of - 1. There are 6 F in the given radical.

Let the oxidation state of Al be x.

The entire radical must have a -3 charge.

Thus x + 6 x (-1) = -3

x - 6 = -3

x = +3

Thus oxidation state = + 3.

There are a total of 6 F which donate electrons for 1 Al.

So covalency is 6.

Answer 2

Answer:

"When aluminium and fluoride are together in aqueous solution, they readily form complex ions such as [AlF6]3-. Electronic configuration of Aluminum is: [Ne] 3s23p1. Al has vacant 'd' orbitals and can expand its octet in [AlF6]- . It has six ligands. Aluminium can accommodate six F atoms. ["