Chemistry, asked by parag8266, 1 year ago

Write the structural formulae of first six homologues of homologous series of straight
chain aliphatic carboxylic acids​

Answers

Answered by pintusingh41122
2

Answer:

Generally, aliphatic carboxylic acids are represented by R-COOH

Here R is an alkyl group.

1. First straight chain aliphatic carboxylic acid is H-COOH = Methanoic acid or Formic acid

2. Second straight chain aliphatic carboxylic acid is CH3-COOH = Ethanoic acid or Acetic acid

3. Third straight chain aliphatic carboxylic acid is CH3-CH2-COOH = Propanoic acid

4. Fourth straight chain aliphatic carboxylic acid is CH3-CH2-CH2-COOH = Butanoic acid

5. Fifth straight chain aliphatic carboxylic acid is CH3-CH2-CH2-CH2-COOH = Pentanoic acid

6. SIxth straight chain aliphatic carboxylic acid is CH3-CH2-CH2-CH2-CH2-COOH = Hexanoic acid

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