Write the zeros of
x^2+2x+1
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ANSWER:-------
given :- x² + 2x + 1
by splitting method we get,
→ x² + (x + x) + 1 = 0
→ x² + x + x + 1 = 0
→ x(x + 1) + 1(x + 1) = 0
→ (x + 1) (x + 1) = 0
hence, x = -1 (x + 1 = 0 => x = -1)
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vijayvargiyashivi:
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Answered by
2
x square + 2x + 1
x square + x + x + 1
x(x+1)+1(x+1)
(x+1)(x+1)
x=-1 or x = -1
x square + x + x + 1
x(x+1)+1(x+1)
(x+1)(x+1)
x=-1 or x = -1
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