Question

Write y=2x^2+8x+10 in vertex form

Answer 1

When we find the vertex, we will also find the axis of symmetry. We will change the function into vertex form.

y = a(x - h)2 + k

in which the vertex is in the form (h, k).

y = -2(x2 + 4x + 4) +18

y = -2(x + 2)2 + 18

If we expand this vertex form, we will get back the standard form.

Therefore, the vertex is (-2, 18).

The axis of symmetry is the x-coordinate of the vertex. The axis of symmetry is x = -2

To find y-intercept, evaluate y when x=0.

To find two other points, which is the x-intercept, set y=0. We can use the vertex form to find the x-intercepts.

-2(x + 2)2 + 18 = 0

-2(x + 2)2 = -18

(x + 2)2 = 9

x + 2 = ± √(9)

x = -2 ± √(9)

x = -2 ± 3

x = -5 and x = 1

The x-intercepts are (-5,0) and (1,0).

Hope it helps u, tq..........