Question

(x-1)2 (x2-5)/(x2+x-1) >=0

Answer 1

Answer:

(x-1)^2 (x^2-5)/(x^2+x-1) >=0

[(x^2-2x+1) (x^2-5)] / (x^2+x-1)>0

[x^2(x^2-2x+1)-5(x^2-2x+1)] / (x^2+x-1) >0

[x^4-2x^3+x^2-5x^2+10x + 5] / (x^2+x-1) >0

[x^4-2x^3-4x^2+10x + 5] / (x^2+x-1) >0

further divide[x^4-2x^3-4x^2+10x + 5]  by (x^2+x-1)