√X - 1/√x if x = 3+2√2
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it can also be written as
x= 2+1+2√2
ie x= (√2)²+1²+2√2(1)
Using identity (a+b)²= a²+b²+2ab
we can solve it easily ,
Now x= (√2+1)²
and √x= √(√2+1)²
i.e √x= √2+1
Then 1/√x= 1/√2+1
on rationalizing it we get
= [1/√2+1]× √2-1/√2-1
= √2-1
Now According to the question
√x-1/√x= √2+1-(√2-1
= √2+1-√2+1
= 2
Hope this helps you......✌^_^
x= 2+1+2√2
ie x= (√2)²+1²+2√2(1)
Using identity (a+b)²= a²+b²+2ab
we can solve it easily ,
Now x= (√2+1)²
and √x= √(√2+1)²
i.e √x= √2+1
Then 1/√x= 1/√2+1
on rationalizing it we get
= [1/√2+1]× √2-1/√2-1
= √2-1
Now According to the question
√x-1/√x= √2+1-(√2-1
= √2+1-√2+1
= 2
Hope this helps you......✌^_^
AkshatMathur:
thanks a lot
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