Question

√x/1+√y/1+x+y+√z/1+x+y+z ‹ √3
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Answer 1

Step-by-step explanation:

Assuming the question to be : x−1y=1,y−1z=2,z−1x=3 then what is xyz =?

x−1y=1⟹x−1=y

y−1z=2⟹y−1=2z⟹y=1+2z=x−1⟹x=2z+2

z−1x=3⟹z−1=3x⟹z−1=6z+6⟹z=−75

⟹x=−45;y=−95

⟹xyz=(−45)⋅(−95)⋅−75=−252125