x = 2^1/3 + 2^-1/3 prove 2x^3 = 6x + 5
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Let the cube root of 2 be y.
=>x = y + 1/y
=>2x^3 = 2(y + 1/y)^3
= 2(y^3 + 1/y^3 + 3y + 3/y)
= 2(y^3 + 1/y^3) + 6(y + 1/y)
Note that y^3 = 2.
=> 2x^3 = 2(2 + 1/2) + 6x (y + 1/y = x as mentioned above)
= 5 + 6x
=>x = y + 1/y
=>2x^3 = 2(y + 1/y)^3
= 2(y^3 + 1/y^3 + 3y + 3/y)
= 2(y^3 + 1/y^3) + 6(y + 1/y)
Note that y^3 = 2.
=> 2x^3 = 2(2 + 1/2) + 6x (y + 1/y = x as mentioned above)
= 5 + 6x
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