Question

x^2-(√2+1)x+√2=0
find the value of x

Answer 1

x = (the above answer).

Answer 2

Heya!!!

Here's your answer friend,

x² - (√2 + 1 )x + √2 = 0
x² -√2x -x + √2 = 0
x(x - √2) -1(x - √2) = 0
(x-√2)(x-1) = 0
x = √2 or x = 1

Hope it helps you :))