x ²-2 (P+1)x+ P2=0, find the value of P
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Answer:
question is wrong. RIGHT QUESTION IS x ²-(2P+1)x+ P2=0,
Step-by-step explanation:
x ²-(2P+1)x+ P2=0,
x ²-2Px-1x+ P2=0,
x(x-2P) - 1(x-2P)
(x-1) (x-2P)
x=1
hence,
2P=x
P=x/2 puting value of x
P=1/2
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