Math, asked by ajaypratapsingh90675, 1 year ago

x^2-2x-15 Factories
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Answers

Answered by Anonymous
14

x^2 - 2x - 15

x^2 - 2x +1 - 16

(x - 1)^2 - 4^2

(x - 1 - 4)(x - 1 + 4)

(x - 5)(x + 3)

using

x^2 - y^2 =( x - y)(x + y)

Answered by ShreyaSingh31
23

\bf{\huge{\underline{\boxed{\sf{\red{Answer:}}}}}}

\bf{\underline{\underline{\sf{\blue {Given\:Equation:}}}}}

  • - 2x - 15

\bf{\underline{\underline{\sf{\blue {To\:find\::}}}}}

  • Value of x

\bf{\underline{\underline{\sf{\blue {Solution:}}}}}

=> \sf{x^2\:-5x\:+3x\:-\:15\:=\:0}

=> \sf{x\:(\:x\:-5)\:3\:(\:x\:-\:5)\:=\:0}

=> \sf{(x\:-\:5)\:\:\:\:\:(\:x\:+\:3\:)=\:0}

=> \sf{x\:-\:5\:=\:0\:\:\:OR\:\:\:\:x\:+\:3\:=\:0}

=> \sf{x\:=\:5\:\:\:\:\:OR\:\:\:\:x\:=\:-\:3}

\bf{\huge{\underline{\boxed{\sf{\red{Verification:}}}}}}

When x = 5,

Equation :-

x² - 2x - 15 = 0

Substitute x = 5 in equation,

=> (5)² - 2 ( 5) - 15 = 0

=> 25 - 10 - 15 = 0

=> 15 - 15 = 0

=> 0 = 0

LHS = RHS .

Similarly we can verify by substuting x = - 3 in equation.

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