Question

x^2/2x=2,is it quadratic equation or not?​

Answer 1

Solution:-

Given:-

$\rm \: \to \: \dfrac{ {x}^{2} }{2x} = 2$

To find it is quadratic equation or not

by simplify we get

$\rm \: \to \: \dfrac{ {x}^{2} }{2x} = 2$

$\rm \: \to \: \dfrac{ {x}^{ \cancel2} }{2 \cancel{x}} = 2$

$\rm \: \to \: x = 4$

General form of quadratic equation is

$\rm \: {a}x^{2} + bx + c = 0 \: \: where \: \: \: a \not = 0$

So given equation is not a quadratic equation

More information about quadratic equation

Definition of Quadratic equation:-

A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0 , where a , b , c are real number and a is not equal to zero

Root of a quadratic equation

A real number α is callled root of the quadratic equation ax² + bx + c = 0 if a ≠ 0 if aα² + bα + c = 0

History

Babylonians were the first to solve the quadratic equation of the form x² - px + q = 0

Brahmagupta an indian mathematician gave an explicit formula to solve a quadratic equation of the form ax² - bx = c

An arab mathematician, AL - Khwarizmi in AD 800 also studied quadratic equations of various types

Answer 2

ANSWER✔

$\therefore To\: check\:whether\: \dfrac{x^2}{2x}=2\: is\:a\:quadracti\:equation\:or\:not.$

$\therefore we\:get,$

$\implies \dfrac{x^{\cancel{2}}}{2\:\:\cancel{x}}=2$

$\implies \dfrac{x}{2}= 2$

$\implies x= 2\times 2$

$\implies x=4$

$\large{\boxed{\bf{ \star\:\: x=4\:\: \star}}}$

$\therefore quadratic\:equation\:can\:be\:written\:as\\ \dashrightarrow ax^2+bc+c=0, \: where\: a \neq 0\\ from \: the \:staement\:we\:can\:say\:that\: \dfrac{x^2}{2x}= 2 \: is \: not \:a \:quadratic\:equation.$

__________