x^2+3y+2
plz solve this fast
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kindly refer to attachment.....
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Correct Question :------
- X² + 3x + 2 = 0 . solve this ?
solving this by splitting the mid-term we get, ,
x²+3x +2 = 0
→ x² +2x +x + 2 = 0
→ x(x+2) + 1(x+2) = 0
Taking (x+2) common now ,,
→ (x+2)(x+1) = 0
putting equal to 0 now we get,
x+2 = 0
→ X = (-2)
x+1 = 0
→ X = (-1) ..
Hence , roots of Equation are (-1) and (-2) ..
(Hope it helps you)
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