Question

x^2 -41x+180 factorise for a​

Answer 1

Answer:

★Answer is = 45, -4.

Step-by-step explanation:

⟹x² - 41x + 180 = 0

⟹x² - 45x + 4x + 180 = 0

⟹X(x-45) + 4(x-45) = 0

⟹(X+4) (x-45) = 0

So From here we got two values of X

⟹X = -4 and X = 45.

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Answer 2

Answer:

Hey

by spilliting the middle term

x^2-41x+180

1•180 = 180

then find the the factors of 180 whose some equals to the coffiecient of the middle term which is -41

x^2 -36 -5x -180

➡️ x•(x-36)

➡️ 5•( x-36)

➡️ Add the both the terms which given above

(x-5)• (x-36)

which is the desire factorization

➡️ At the end

(x- 5) •(x-36)=0

➡️ Now solving the variable equation

➡️ x-5=0

x=5

➡️ x-36=0

x = 36

Hence Prove:

x=5

x=36

Step-by-step explanation:

Hope its help uhh....

Thank You ‼️