Question

X^2-4root2x+6=0 by completing square

Answer 1

as per your question,

x^2 - 4√2x+6 = 0

x^2- 3√2 - √2 + 6 = 0

so,

x(x-3√2) - √2(x- 3√2) =0

(x - √2)(x - 3√2) =0

hence ,

x = √2 and 3√2