Question

X^2-(m-3)x+m=0 find the value of m for which the roots are positive in sign

Answer 1

Hope u like my process
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Given:-
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=>f(x) =x² - (m-3) +m =0

Note,
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The quadratic equation will have positive roots if and only if the equation is in the form of

$= > {x}^{2} - 2ax + {a }^{2} = 0$
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Thus, comparing we can say that,

$= > if \: \: \: \bf m \leqslant 3$


either of one root will be negative.
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So,

The value of M should be greater than 3.

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