x^2+x-20=0 solve the following using complete the square method.
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☆ Answer:
The solutions are x=4,x=−5
☆ Explanation:
x2+x−20=0
We can Split the Middle Term of this expression to factorise it.
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅(−20)=−20
AND
N1+N2=b=1
After trying out a few numbers we get N1=−4 and N2=5
(−4)⋅5=−20, and 5+(−4)=1
x2+x−20=x2+5x−4x−20
=x(x+5)−4(x+5)
(x+5) is a common factor to each of the terms
=(x−4)(x+5)
We equate both factors to zero and obtain the solutions:
x−4=0,x=4x+5=0,x=−5
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :-♡♡《 Nitish kr singh 》♡♡
☆ Answer:
The solutions are x=4,x=−5
☆ Explanation:
x2+x−20=0
We can Split the Middle Term of this expression to factorise it.
In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:
N1⋅N2=a⋅c=1⋅(−20)=−20
AND
N1+N2=b=1
After trying out a few numbers we get N1=−4 and N2=5
(−4)⋅5=−20, and 5+(−4)=1
x2+x−20=x2+5x−4x−20
=x(x+5)−4(x+5)
(x+5) is a common factor to each of the terms
=(x−4)(x+5)
We equate both factors to zero and obtain the solutions:
x−4=0,x=4x+5=0,x=−5
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :-♡♡《 Nitish kr singh 》♡♡
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