(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=0 this is too hard
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May you tell me the Answer Please ???
Answers
Answered by
0
(x+2)(x+3)+(x-3)(x-2)-2x(x+1)=
X^2+3x+2x+6+x^2-2x-3x-5-2x^2-2y=
X^2+x^2-2x^2+3x+2x-2x-3x-2x+6-5=
-2x+1
X^2+3x+2x+6+x^2-2x-3x-5-2x^2-2y=
X^2+x^2-2x^2+3x+2x-2x-3x-2x+6-5=
-2x+1
Answered by
39
Solution:-
=>(x+2) (x+3) + (x-3) (x-2) -2x(x+1) = 0
=>(x²+3x+2x+6 )+(x²-2x-3x+6)
-2x²-2x = 0
=> x²+5x+6 + x²-5x+6 - 2x² - 2x = 0
we can write it as
=> x²+x²-2x² +5x-5x -2x +6+6 = 0
=> 2x²-2x² - 2x + 12 = 0
=> - 2x + 12 = 0
=> - 2x = - 12
=> 2x = 12
=> x = 12/2
=> x = 6
i hope it helps you.
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