Question

x^2 - x - (a^2 + a) = 0 solve by factorisation

Answer 1

b^2-4ac≥0 then have the real root then have the factorisation

(1)^2-4*(1*(-(a^2+a)))≥0

1+4a^2+4a≥0

(2a+1)^2≥0

we know that the formula

(-b+√(b^2-4ac))/2a and (-b-√(b^2-4ac))/2a=x(the root of the equation)

(1+2a+1)/2=x and (1-2a-1)/2=x

a+1=x and -a=x

factorisation of the equation is (x-a-1)(x+a)