x=2, y=-1 is a solution of the linear equation
A. x+2y=0
B. x+2y=4
C. 2x+y=0
D. 2x+y=5
Answers
Given : x = 2 and y = -1
(a) Given linear equation is x + 2y = 0
On putting x = 2 and y = -1 in LHS :
2 + 2 × - 1
2 - 2
= 0
= RHS
which is TRUE
Hence, x + 2y = 0 is the linear equation.
(b) Given linear equation is x + 2y = 4
On putting x = 2 and y = -1 in LHS :
2 + 2 × - 1
2 - 2
0 ≠ 4
LHS ≠ RHS
Hence, x + 2y = 4 is not the linear equation.
(C) Given linear equation is 2x + y = 0
On putting x = 2 and y = -1 in LHS :
2 × 2 + (- 1)
4 - 1
3 ≠ 0
LHS ≠ RHS
Hence, 2x + y = 0 is not the linear equation.
(d) Given linear equation is 2x + y = 5
On putting x = 2 and y = -1 in LHS :
2 × 2 + - 1
4 - 1
3 ≠ 5
LHS ≠ RHS
Hence, 2x + y = 5 is not the linear equation.
Option (A) x + 2y = 0 is correct.
HOPE THIS ANSWER WILL HELP YOU…..
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Given : x = 2 and y = -1
(a) Given linear equation is x + 2y = 0
On putting x = 2 and y = -1 in LHS :
2 + 2 × - 1
2 - 2
= 0
= RHS
which is TRUE
Hence, x + 2y = 0 is the linear equation.
(b) Given linear equation is x + 2y = 4
On putting x = 2 and y = -1 in LHS :
2 + 2 × - 1
2 - 2
0 ≠ 4
LHS ≠ RHS
Hence, x + 2y = 4 is not the linear equation.
(C) Given linear equation is 2x + y = 0
On putting x = 2 and y = -1 in LHS :
2 × 2 + (- 1)
4 - 1
3 ≠ 0
LHS ≠ RHS
Hence, 2x + y = 0 is not the linear equation.
(d) Given linear equation is 2x + y = 5
On putting x = 2 and y = -1 in LHS :
2 × 2 + - 1
4 - 1
3 ≠ 5
LHS ≠ RHS
Hence, 2x + y = 5 is not the linear equation.
Option (A) x + 2y = 0 is correct.
HOPE THIS ANSWER WILL HELP YOU…..