Math, asked by GayatriJha, 10 months ago

x^2+y^2=7xy then log [1/3 (x+y) ]=

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Answered by sinanckofficial

8

Answer:

If x^2 + y^2 = 7xy, show that log [(x + y)/3] = (log x + log y)/2?

Answered by pavit15

4

Answer:

If x^2 + y^2 = 7xy, show that log [(x + y)/3] = (log x + log y)/2?

Step-by-step explanation:

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