Math, asked by anushka4444, 1 year ago

x^2 - y! =2001 find all possible values.of x and y

Answers

Answered by ZiaAzhar89
0
X^2 - Y^2=2001
(X+Y)(X-Y)=667×3

possible value
1)X+Y=667 X-Y=3

2)X+Y=3 X-Y=667

3)X+Y= -667 X-Y= -3

4)X+Y= -3 X-Y= -667

Rest solve it

Hope this help u if I am understanding ur questions correctly.

anushka4444: possible?
ZiaAzhar89: please message original question pic to me if i then i will try to solve it
anushka4444: ok
anushka4444: actually this question is asked by my friend
ZiaAzhar89: i didnt get the question u understand na
anushka4444: ok
ZiaAzhar89: y! means
anushka4444: factorail
anushka4444: 5!=5*4*3"2*1
anushka4444: 5!=5*4*3*2*1
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