X^{20} द्वितीय कोटि के अवकलज ज्ञात कीजिए
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d²y/dx² = 380 x¹⁸ यदि y = x²⁰
Step-by-step explanation:
द्वितीय कोटि के अवकलज ज्ञात कीजिए
y = x²⁰
dy/dx = d(x²⁰)/dx
=> dy/dx = 20x¹⁹
d²y/dx² = d( 20x¹⁹)/dx
=> d²y/dx² = 20 * 19 x¹⁸
=> d²y/dx² = 380 x¹⁸
और अधिक जानें :
sin(x²+5)"
brainly.in/question/15286193
sin (ax+b) फलन का अवकलन कीजिए
brainly.in/question/15286166
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