x^-22x+120 solve full factorise
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x^2-(12+10)x+120
x^2-12x-10x+120
x(x-12)-1(x-12)
(x-1)(x-12)
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x²-22x+120 =0
x²-12x-10x+120 = 0
x(x-12) -10(x-12) =0
(x-12) (x-10) =0
x-12=0 or x-10= 0
x=12 or x=10
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