Question

x-2y=-2 ; x+2y=10 Solve the simultaneous equation.

Answer 1

$\textbf{Answer}$

Given equations are,
$\textbf{x - 2y = - 2}$ -----(1)
$\textbf{x + 2y = 10}$ -----(2)

$\textbf{Subtract equation (2) by (1),}$

=> (x - 2y) - (x + 2y) = - 2 - 10

=> - 2y - 2y = - 12

=> - 4y = - 12

=> y = 3

$\textbf{Substitute value of y in equation (1)}$,
x - 2y = - 2
=> x - 2(3) = - 2
=> x - 6 = - 2
=> x = - 2 + 6
=> x = 4

$\textbf{Value of x = 4}$
$\textbf{Value of y = 3}$


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Answer 2

Solution :

Given simultaneous equations are

x - 2y = -2 ----( 1 )

x + 2y = 10 -----( 2 )

Add ( 1 ) & ( 2 ) , we get

2x = 8

=> x = 8/2

x = 4

substitute x = 4 in equation ( 2 ), we get

4 + 2y = 10

=> 2y = 10 - 4

=> y = 6/2

=> y = 3

Therefore ,

x = 4 , y = 3

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