Question

x+2y=3
x-y=3
x+y=3 find the inclosed by line​

Answer 1

Answer:

Correct option is

C

16log2+3

Given the curve, xy−3x−2y−10=0

Step-by-step explanation:

⇒xy−2y=3x+10

⇒y(x−2)=3x+10

⇒y=

x−2

3x+10

∴ Area bounded by the curve xy−3x−2y−10=0, x-axis and the lines x=3,x=4,

∫

3

4

∣y∣dx

=∫

3

4

(

x−2

3x+10

)dx

=∫

3

4

(

x−2

3x−6+16

)dx

=∫

3

4

(3+

x−2

16

)dx

=[3x+16log∣x−2∣]

3

4

=[12+16log∣2∣−9−16log∣1∣]