(X+3)^2 using suitable identity
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Answered by
27
Answer :
We know that,
(a + b)² = a² + 2ab + b²
We have to expand (x + 3)²
Then, (x + 3)²
= x² + (2 * x * 3) + 3²
= x² + 6x + 9
Answered by
2
To factorize :-
( x + 3 )²
using suitable identity.
Step by step explanation:-
we have,
(a + b )² = a² + b² + 2ab
put a = x and b = 3 in given identity.
( x + 3)² = x² + (3)² + 2.x.3
(x + 3)² = x² + 9 +6x ans.
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