x^3-3x^2-9x-5 factorise
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Answered by
5
Answer:
=X³ - 3x² - 9x - 5
= x³ + x² - 4x² - 4x - 5x - 5
= x²( x + 1) - 4x ( x + 1) - 5(x + 1)
= (x + 1)(x² - 4x - 5)
= (x + 1)(x² -5x + x - 5)
= (x + 1)(x - 5) (x + 1)
Answered by
1
Step-by-step explanation:
Given Equation is x^3 - 3x^2 - 9x - 5
= > x^3 - 4x^2 + x^2 - 5x - 4x - 5
= > x^3 - 4x^2 - 5x + x^2 - 4x - 5
= > x(x - 4x - 5) + 1(x^2 - 4x - 5)
= > (x + 1)(x^2 - 4x - 5)
= > (x + 1)(x^2 + x - 5x - 5)
= > (x + 1)(x(x + 1) - 5(x + 1))
= > (x + 1)(x + 1)(x - 5)
= > (x + 1)^2(x - 5).
Hope this helps!
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