X^3-3x^2-x+3 factorize please
Answers
Answered by
2
Hey Friend ☺
x^3 - 3x^2 - x + 3
= x^2 ( x - 3 ) - 1 ( x - 3 )
= ( x - 3 )( x^2 - 1 )
= ( x - 3 )[ ( x )^2 - ( 1 )^2 ]
= ( x - 3 )( x - 1 )( x + 1 )
Hope of helps you ..!!
✌
x^3 - 3x^2 - x + 3
= x^2 ( x - 3 ) - 1 ( x - 3 )
= ( x - 3 )( x^2 - 1 )
= ( x - 3 )[ ( x )^2 - ( 1 )^2 ]
= ( x - 3 )( x - 1 )( x + 1 )
Hope of helps you ..!!
✌
Answered by
1
= x^3-3x^2-x+3
= x^2(x-3) -1(x-3)
= [(x^2-1)(x-3)]
= x^2(x-3) -1(x-3)
= [(x^2-1)(x-3)]
Similar questions