x^3-3x^2-x+3 what will be the answer
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I think question is to factorise it.
= x^3-3x^2-x+3
= x^2 (x-3) - 1(x-3)
= (x^2 - 1) (x-3)
= (x^2 - 1^2) (x-3)
= (x+1) (x-1) (x-3)
Hope it's helpful to u.
= x^3-3x^2-x+3
= x^2 (x-3) - 1(x-3)
= (x^2 - 1) (x-3)
= (x^2 - 1^2) (x-3)
= (x+1) (x-1) (x-3)
Hope it's helpful to u.
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