Question

(x_3)/4+(x-1)/5_(x_2)/3=1​

Answer 1

Answer:

$\frac{x - 3}{4} + \frac{x + 1}{5} - ( \frac{x - 2}{3}) = 1 \\ \\ \frac{9x - 11}{20} - ( \frac{x - 2}{3} ) = 1 \\ \\ \frac{7x + 7}{60} = 1 \\ \\ 7x + 7 = 60 \\ \\ 7x = 53 \\ \\ x = \frac{53}{7}$