x^3-5x^2-x +5
please help me to solve this maths question
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x^3-5x^2-x+5=0
Use a method called "factoring by grouping", which only works when the polynomial has four terms.
(x^2)(x-5)-x+5=0
Factor out an (x^2) from the first two terms.
(x^2)(x-5)(-1)(x-5)=0
Factor out a (-1) from the 2nd two terms.
(x^2)(-1))(x-5)=0
(x+1)(x-1)(x-5)=0
Factor the term using the difference of squares formula
(a^2-b^2)=(a+b)(a-b)
Set each factor equal to zero and solve.
x+1=0, x-1=0, x-5=0
x=-1, x=1, x=5
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