Question

x^3-6x^2+11x-6=0 then what is the value of x​

Answer 1

Answer:

Let' s make it simple and quick

Step-by-step explanation:

f(x)=x^3-6x^2+11x-6=0

at x =1

f(1)= 1^3 -6(1)^2+11(1)-6

=1-6+11-6

=-5+11-6

=0

f(1)=0=RHS

So ,x=1

Answer 2

Answer:

3,2,1

Step-by-step explanation:

at  x=1

=>    x^3-6x^2+11x-6=0

=> x=1 is a root of equation

divide x^3-6x^2+11x-6=0 by x-1

quotient will be x^2-5x+6

whic further factorise to (x-3)(x-2)

x^3-6x^2+11x-6 = (x-3)(x-2)(x-1)=0

therefore x=3,2,1