Question

X^3+7X^2+14X+8=0 find value of X.

Answer 1

x^3 + 7x^2 + 14 x +8 =0
= putting the value of x as -1 .
then (-1)^3 + 7 × (-1)^2 + 14 ×(-1) + 8 .
= -1+7-14+8.
= -15+15= 0.
when we put the value of x =-1 The whole equation gets 0 . then (x+1) is a factor of this.
Divide the whole equation by (x+1) .
then we get a quadratic equation x^2 + 6x +8.
then after factorize it we get (x+2) (x+4) .
then the value of x = -2
x= -4
and x = -1.
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