Question

x^3+xy(1-3x)-3y^2 factorise the following​

Answer 1

Answer:

1/2x + 1/3y = 2 (ii) 2/x^0.5 + 3/y^0.5 = 2

1/3x + 1/2y = 13/6 4/x^0.5 - 9/y^0.5 = -1

(iii) 4/x + 3y = 14 (iv) 5/(x-1) + 1/(y-2) = 2

3/x - 4y = 23 6/(x-1) - 3/(y-2) = 1

(v) (7x-2y) / xy = 5 (vi) 6x+3y=6xy

(8x+7y) / xy = 15 2x+4y=5xy

(vii) 10/(x+y) + 2/(x-y) = 4 (viii) 1/(3x+y) + 1/(3x-y) = 3/4

15/(x+y) - 5/(x-y) = -2 1/[2(3x+y)] - 1/[2(3x-y)] = -1/8

Step-by-step explanation:

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Answer 2

Answer:

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