Question

x/3 +y/4= 1= 0 in the form of ax+ bx+ c= 0​

Answer 1

Answer:

xy/12 = 1 = 0

Step-by-step explanation:

= x/3+y/4=1=0

= x+y/12=1=0

= xy/12=1=0

Answer 2

Answer:

$4x + 3y - 12 = 0$

Step-by-step explanation:

Note: Assuming your original equation to be:

$\frac{x}{3} + \frac{y}{4} - 1 = 0$

LCM of 3 & 4 = 12

Simplifying:

$\frac{4x + 3y - 12}{12} = 0$

$4x + 3y - 12 = 0$

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