X=30+20t^2 find instantaneous velocity and the acceleration where t=2sec what are the initial position and velocity of object
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Answer:
instantaneous velocity=80m/s
40m/s^2 is the acceleration
30m is initial position
30m/s is velocity of object
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EXPLANATION
x = 30+ 20t^2
here , t = 2sec
1.) instantaneous velocity = dx/dt
= dx/dt = d(30+20t^2)/dt
= 40t ,(t=2 )
= 40x2
= 80 m
2. Instantaneous
acceleration
= dv/dt
= d(40t)/dt
= 40 m/s^2
3. initial position = 30 m
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