Math, asked by kaushikraj007, 1 year ago

x=√5-√3/√5+√3 y=√5+√3/√5-√3 find the value of x²+xy+y²/x²-xy+y²

Answers

Answered by rajivnld2002p7qvsa
0
x+y=2*(15+9)/2=24
x*y=1
now, expression may be re-written as,
(x+y)^2-xy/(x+y)^2+xy
576-1/576+1
575/577
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