Question

x-a/b+c+x-b/c+a+x-c/a+b=3
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Answer 1

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Answer 2

Answer:

x = (a + b + c)

Step-by-step explanation:

In the given set of equations,

We have been given that,

$\frac{x-a}{b+c}+\frac{x-b}{c+a}+\frac{x-c}{a+b}=3$

Therefore, on the further simplification of the equation, we can say that,

$(\frac{x-a}{b+c}-1)+(\frac{x-b}{c+a}-1)+(\frac{x-c}{a+b}-1)=0\\(\frac{x-a-b-c}{b+c})+(\frac{x-b-c-a}{c+a})+(\frac{x-c-a-b}{a+b})=0\\(x-a-b-c)(\frac{1}{b+c}+\frac{1}{c+a}+\frac{1}{a+b})=0$

Now, we have this equation for this to be true,

The only condition is, when,

x - a - b - c = 0

x - (a + b + c) = 0

x = (a + b + c)

Therefore, the required value of 'x' is given by, when,

x = (a + b + c)

Hence, we can say that the value of x is (a + b + c).